x^2+180x+1000=0

Solution for x^2+180x+1000=0 equation:

x^2+180x+1000=0

a = 1; b = 180; c = +1000;
Δ = b2-4ac
Δ = 1802-4·1·1000
Δ = 28400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28400}=\sqrt{400*71}=\sqrt{400}*\sqrt{71}=20\sqrt{71}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-20\sqrt{71}}{2*1}=\frac{-180-20\sqrt{71}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+20\sqrt{71}}{2*1}=\frac{-180+20\sqrt{71}}{2}
$